Section: AP Calc AB


18) Find the absolute maximum of f(x) = 3x4 – 4x3 on [-2,3]

Explanation

f’(x) = 12x3 – 12x2 ⇒ Critical numbers: 0 and 1. On interval [-2,3], we have: f(-2) = 80, f(0) = 0, f(1) = -1 and f(3) = 135. Therefore, fmax = 135.
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