Section: AP Calc AB

14) Find an equation of the tangent line to y= -2x² + 2x + 1 at the point (-1,0)

1. y = 3x + 3y = 3x + 3
2. y = 6x + 6
3. y = - 3x - 3
4. y= -6x - 6

We have f’(x) = -4x + 2 ⇒ f’(-1) = 6. Therefore, y = 0 + 6 (x-(-1)) = 6x + 6