Section: AP Calc AB

10) The slope of the tangent to the curve y³x +y²x² = 6 at (2,1) is

1. 5/2
2. 3/2
3. -(5/14)
4. -(3/14)

We have d/dx (y³x +y²x²) = y³ + 3y²x dy/dx + 2xy² + 2x²y dy/dx

So, dy/dx =

-	y3 + 2xy2
	2x2y + 3y2x

 = -(5/14)