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| Author | Topic |
| Anry | Posted - 3 April 2019 17:11  X=3, Y=-3, and Z=5 -3xy[to the second power] - -Z/3XZ The fraction is written vertically in the equation, so its clear that only the numerator is negative. The answer is -56, but for the life of me I cant figure out how to apply the order of operations to the fraction. |
| hdbalzac | Posted - 5 November 2021 6:21 X = 3, Y = -3, Z = 5</P><P>f(X,Y,Z) = -3·X·Y^2 - -Z / 3·X·Z</P><P>f(X,Y,Z) = -3·X·Y^2 + Z / 3·X·Z</P><P>And using parentheses to make it clearer;</P><P>f(X,Y,Z) = -3·X·(Y^2) + (Z / 3)·X·Z</P><P>Substituting the numbers 3, -3, 5 given for the variables X, Y, and Z respectively;</P><P>f(3, -3, 5) = -3·3·[ (-3)^2 ] + (5 / 3)·3·5 =</P><P>-27·9 + 5·5 =</P><P>-81 + 25 =</P><P>-56. |
| hdbalzac | Posted - 5 November 2021 6:24 It looks the dot symbol makes a mess. Herer is the link to the solution:<BR>https://i72.servimg.com/u/f72/19/97/10/39/ged_ma10.png |
| hdbalzac | Posted - 5 November 2021 6:39 I later noticed the typo -27 in the reply I gave as the picture on that link which should read -9. |
